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2017 Apr 200-105 practice test

Q1. - (Topic 3) 

Refer to the exhibit. 

The show interfaces serial 0/1 command was issued on the R10-1 router. Based on the output displayed which statement is correct? 

A. The cable connected to the serial 0/1 interface of the R10-1 router is a DTE cable. 

B. The R10-1 router can ping the router interface connected to the serial 0/1 interface. 

C. The clock rate used for interface serial 0/1 of the R10-1 router is 1,544,000 bits per second. 

D. The CSU used with the serial 0/1 interface of the R10-1 router has lost connection to the service provider. 

E. The interface of the remote router connected to the serial 0/1 interface of the R10-1 router is using the default serial interface encapsulation. 

Answer:

Explanation: 

Cisco High-Level Data Link Controller (HDLC) is the Cisco proprietary protocol for Cisco HDLC is the default encapsulation type for the serial interfaces. 


Q2. - (Topic 3) 

Which protocol is an open standard protocol framework that is commonly used in VPNs, to provide secure end-to-end communications? 

A. RSA 

B. L2TP 

C. IPsec 

D. PPTP 

Answer:

Explanation: 

Internet Protocol Security (IPsec) is a technology protocol suite for securing Internet Protocol (IP) communications by authenticating and/or encrypting each IP packet of a communication session. IPsec also includes protocols for establishing mutual authentication between agents at the beginning of the session and negotiation of cryptographic keys to be used during the session. 


Q3. - (Topic 3) 

What is the purpose of Inverse ARP? 

A. to map a known IP address to a MAC address 

B. to map a known DLCI to a MAC address 

C. to map a known MAC address to an IP address 

D. to map a known DLCI to an IP address 

E. to map a known IP address to a SPID 

F. to map a known SPID to a MAC address 

Answer:

Explanation: 

http://www.ciscopress.com/articles/article.asp?p=170741&seqNum=4 

Frame-Relay (a Layer 2 protocol) uses Inverse-Arp to map a know Layer 2 Address (DLCI) to a unknow Layer 3 Address. Dynamic Mapping Dynamic address mapping relies on the Frame Relay Inverse Address Resolution Protocol (Inverse ARP), defined by RFC 1293, to resolve a next hop network protocol address to a local DLCI value. The Frame Relay router sends out Inverse ARP requests on its Frame Relay PVC to discover the protocol address of the remote device connected to the Frame Relay network. The responses to the Inverse ARP requests are used to populate an address-to-DLCI mapping table on the Frame Relay router or access server. The router builds and maintains this address-to-DLCI mapping table, which contains all resolved Inverse ARP requests, including both dynamic and static mapping entries. When data needs to be transmitted to a remote destination address, the router performs a lookup on its routing table to determine whether a route to that destination address exists and the next hop address or directly connected interface to use in order to reach that destination. Subsequently, the router consults its address-to-DLCI mapping table for the local DLCI that corresponds to the next hop address. Finally, the router places the frames targeted to the remote destination on its identified outgoing local DLCI. On Cisco routers, dynamic Inverse ARP is enabled by default for all network layer protocols enabled on the physical interface. Packets are not sent out for network layer protocols that are not enabled on the physical interface. For example, no dynamic Inverse ARP resolution is performed for IPX if ipx routing is not enabled globally and there is no active IPX address assigned to the interface. Because dynamic Inverse ARP is enabled by default, no additional Cisco IOS command is required to enable it on an interface. Example 4-16 shows the output of the show frame-relay map privileged EXEC mode command. The addressto-DLCI mapping table displays useful information. The output of the command shows that the next hop address 172.16.1.2 is dynamically mapped to the local DLCI 102, broadcast is enabled on the interface, and the interface's status is currently active. 

NOTE After enabling Frame Relay on the interface, the Cisco router does not perform Inverse ARP until IP routing is enabled on the router. By default, IP routing is enabled on a Cisco router. If IP routing has been turned off, enable IP routing with the ip routing command in the global configuration mode. After IP routing is enabled, the router performs Inverse ARP and begins populating the address-to-DLCI mapping table with resolved entries. 


Q4. - (Topic 2) 

A network administrator is troubleshooting an EIGRP problem on a router and needs to confirm the IP addresses of the devices with which the router has established adjacency. The retransmit interval and the queue counts for the adjacent routers also need to be checked. What command will display the required information? 

A. Router# show ip eigrp adjacency 

B. Router# show ip eigrp topology 

C. Router#show ip eigrp interfaces 

D. Router#show ip eigrp neighbors 

Answer:

Explanation: 

Implementing EIGRP http://www.ciscopress.com/articles/article.asp?p=1171169&seqNum=3Below is an example of the show ip eigrp neighbors command. The retransmit interval (Smooth Round Trip Timer – SRTT) and the queue counts (Q count, which shows the number of queued EIGRP packets) for the adjacent routers are listed: R1#show ip eigrp neighbors IP-EIGRP neighbors for process 1 H Address Interface Hold Uptime SRTT RTO Q Seq (sec) (ms) Cnt Num 

0 10.10.10.2 Fa0/0 12 00:00:39 1282 5000 0 3 


Q5. - (Topic 2) 

Refer to the exhibit. 

The network is converged. After link-state advertisements are received from Router_A, what information will Router_E contain in its routing table for the subnets 208.149.23.64 and 208.149.23.96? 

A. O 208.149.23.64 [110/13] via 190.173.23.10, 00:00:07, FastEthernet 0/0 O 208.149.23.96 [110/13] via 190.173.23.10, 00:00:16, FastEthernet 0/0 

B. O 208.149.23.64 [110/1] via 190.172.23.10, 00:00:07, Serial 1/0 O 208.149.23.96 [110/3] via 190.173.23.10, 00:00:16, FastEthernet 0/0 

C. O 208.149.23.64 [110/13] via 190.172.23.10, 00:00:07, Serial 1/0 O 208.149.23.96 [110/13] via 190.172.23.10, 00:00:16, Serial 1/0 O 208.149.23.96 [110/13] via 190.173.23.10, 00:00:16, FastEthernet 0/0 

D. O 208.149.23.64 [110/3] via 190.172.23.10, 00:00:07, Serial 1/0 O 208.149.23.96 [110/3] via 190.172.23.10, 00:00:16, Serial 1/0 

Answer:

Explanation: 

Router_E learns two subnets subnets 208.149.23.64 and 208.149.23.96 via Router_A through FastEthernet interface. The interface cost is calculated with the formula 108 / 

Bandwidth. For FastEthernet it is 108 / 100 Mbps = 108 / 100,000,000 = 1. Therefore the cost is 12 (learned from Router_A) + 1 = 13 for both subnets - B is not correct. 

The cost through T1 link is much higher than through T3 link (T1 cost = 108 / 1.544 Mbps = 

64; T3 cost = 108 / 45 Mbps = 2) so surely OSPF will choose the path through T3 link -> 

Router_E will choose the path from Router_A through FastEthernet0/0, not Serial1/0 - C & 

D are not correct. 

In fact, we can quickly eliminate answers B, C and D because they contain at least one subnet learned from Serial1/0 - they are surely incorrect. 


Updated 200-105 download:

Q6. - (Topic 1) 

Refer to the exhibit. 

What commands must be configured on the 2950 switch and the router to allow communication between host 1 and host 2? (Choose two.) 

A. Router(config)# interface fastethernet 0/0 Router(config-if)# ip address 192.168.1.1 255.255.255.0 Router(config-if)# no shut down 

B. Router(config)# interface fastethernet 0/0 Router(config-if)# no shut down Router(config)# interface fastethernet 0/0.1 Router(config-subif)# encapsulation dot1q 10 Router(config-subif)# ip address 192.168.10.1 255.255.255.0 

Router(config)# interface fastethernet 0/0.2 Router(config-subif)# encapsulation dot1q 20 Router(config-subif)# ip address 192.168.20.1 255.255.255.0 

C. Router(config)# router eigrp 100 Router(config-router)# network 192.168.10.0 Router(config-router)# network 192.168.20.0 

D. Switch1(config)# vlan database Switch1(config-vlan)# vtp domain XYZ Switch1(config-vlan)# vtp server 

E. Switch1(config)# interface fastethernet 0/1 Switch1(config-if)# switchport mode trunk 

F. Switch1(config)# interface vlan 1 Switch1(config-if)# ip default-gateway 192.168.1.1 

Answer: B,E 

Explanation: 

The two answers B and E list all the commands needed to configure interVLAN routing. Please notice that Cisco switch 2950, 2960 only support dot1Q trunking so we don’t need to specify which trunking encapsulation to use in this case. For Cisco switches 3550 or above we have to use these commands instead: 

Switch3550(config-if)#switchport trunk encapsulation dot1q Switch3550(config-if)#switchport mode trunk 

References: http://www.cisco.com/en/US/tech/tk389/tk815/technologies_configuration_example09186a 00800949fd.shtml https://learningnetwork.cisco.com/servlet/JiveServlet/download/5669-2461/Router%20on%20a%20Stick.pdf. 


Q7. - (Topic 2) 

Refer to the exhibit. 

A packet with a source IP address of 192.168.2.4 and a destination IP address of 10.1.1.4 arrives at the AcmeB router. What action does the router take? 

A. forwards the received packet out the Serial0/0 interface 

B. forwards a packet containing an EIGRP advertisement out the Serial0/1 interface 

C. forwards a packet containing an ICMP message out the FastEthemet0/0 interface 

D. forwards a packet containing an ARP request out the FastEthemet0/1 interface 

Answer: C Explanation: 

CCNA - EIGRP Common Question http://www.orbitco-ccna-pastquestions.com/CCNA---EIGRP-Common-Question.php 

Looking at the output above, there is no IP route for 10.1.1.4 address on AcmeB routing table. If the router can no find a specific path in its routing table to a particular route,( In this case no path is found so AcmeB) the router will inform the source host with an ICMP message that the destination is unreachable and this will be through the same interface it has received the packet (interface Fa0/0 network 192.168.3.0/28 from the exhibit). 

Topic 3, WAN Technologies 


Q8. - (Topic 3) 

Which two statements about using the CHAP authentication mechanism in a PPP link are true? (Choose two.) 

A. CHAP uses a two-way handshake. 

B. CHAP uses a three-way handshake. 

C. CHAP authentication periodically occurs after link establishment. 

D. CHAP authentication passwords are sent in plaintext. 

E. CHAP authentication is performed only upon link establishment. 

F. CHAP has no protection from playback attacks. 

Answer: B,C 

Explanation: 

Understanding and Configuring PPP CHAP Authentication http://www.cisco.com/en/US/tech/tk713/tk507/technologies_tech_note09186a00800b4131. shtml 

One-Way and Two-Way Authentication CHAP is defined as a one-way authentication method. However, you use CHAP in both directions to create a two-way authentication. Hence, with two-way CHAP, a separate three-way handshake is initiated by each side. In the Cisco CHAP implementation, by default, the called party must authenticate the calling party (unless authentication is completely turned off). Therefore, a one-way authentication initiated by the called party is the minimum possible authentication. However, the calling party can also verify the identity of the called party, and this results in a two-way authentication. One-way authentication is often required when you connect to non-Cisco devices. 


Q9. - (Topic 2) 

Refer to the exhibit. 

Assume that all router interfaces are operational and correctly configured. In addition, assume that OSPF has been correctly configured on router R2. How will the default route configured on R1 affect the operation of R2? 

A. Any packet destined for a network that is not directly connected to router R1 will be dropped. 

B. Any packet destined for a network that is not directly connected to router R2 will be dropped immediately. 

C. Any packet destined for a network that is not directly connected to router R2 will be dropped immediately because of the lack of a gateway on R1. 

D. The networks directly connected to router R2 will not be able to communicate with the 172.16.100.0, 172.16.100.128, and 172.16.100.64 subnetworks. 

E. Any packet destined for a network that is not referenced in the routing table of router R2 will be directed to R1. R1 will then send that packet back to R2 and a routing loop will occur. 

Answer:

Explanation: 

First, notice that the more-specific routes will always be favored over less-specific routes regardless of the administrative distance set for a protocol. In this case, because we use OSPF for three networks (172.16.100.0 0.0.0.3, 172.16.100.64 0.0.0.63, 172.16.100.128 0.0.0.31) so the packets destined for these networks will not be affected by the default route. The default route configured on R1 "ip route 0.0.0.0 0.0.0.0 serial0/0 will send any packet whose destination network is not referenced in the routing table of router R1 to R2, it doesn't drop anything so answers A, B and C are not correct. D is not correct too because these routes are declared in R1 and the question says that "OSPF has been correctly configured on router R2, so network directly connected to router R2 can communicate with those three subnetworks. As said above, the default route configured on R1 will send any packet destined for a network that is not referenced in its routing table to 

R2; R2 in turn sends it to R1 because it is the only way and a routing loop will occur. 


Q10. - (Topic 2) 

Refer to the exhibit. 

The Lakeside Company has the internetwork in the exhibit. The administrator would like to reduce the size of the routing table on the Central router. Which partial routing table entry in the Central router represents a route summary that represents the LANs in Phoenix but no additional subnets? 

A. 10.0.0.0/22 is subnetted, 1 subnets D 10.0.0.0 [90/20514560] via 10.2.0.2, 6w0d, Serial0/1 

B. 10.0.0.0/28 is subnetted, 1 subnets D 10.2.0.0 [90/20514560] via 10.2.0.2, 6w0d, Serial0/1 

C. 10.0.0.0/30 is subnetted, 1 subnets D 10.2.2.0 [90/20514560] via 10.2.0.2, 6w0d, Serial0/1 

D. 10.0.0.0/22 is subnetted, 1 subnets D 10.4.0.0 [90/20514560] via 10.2.0.2, 6w0d, Serial0/1 

E. 10.0.0.0/28 is subnetted, 1 subnets D 10.4.4.0 [90/20514560] via 10.2.0.2, 6w0d, Serial0/1 

F. 10.0.0.0/30 is subnetted, 1 subnets D 10.4.4.4 [90/20514560] via 10.2.0.2, 6w0d, Serial0/1 

Answer:

Explanation: 

All the above networks can be summarized to 10.0.0.0 network but the question requires to “represent the LANs in Phoenix but no additional subnets” so we must summarized to 

10.4.0.0 network. The Phoenix router has 4 subnets so we need to “move left” 2 bits of “/24-> /22 is the best choice - D is correct.