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Q121. - (Topic 3) 

If an Ethernet port on a router was assigned an IP address of 172.16.112.1/20, what is the maximum number of hosts allowed on this subnet? 

A. 1024 

B. 2046 

C. 4094 

D. 4096 

E. 8190 

Answer:

Explanation: 

Each octet represents eight bits. The bits, in turn, represent (from left to right): 128, 64, 32 , 16 , 8, 4, 2, 1 Add them up and you get 255. Add one for the all zeros option, and the total is 256. Now, take away one of these for the network address (all zeros) and another for the broadcast address (all ones). Each octet represents 254 possible hosts. Or 254 possible networks. Unless you have subnet zero set on your network gear, in which case you could conceivably have 255. The CIDR addressing format (/20) tells us that 20 bits are used for the network portion, so the maximum number of networks are 2^20 minus one if you have subnet zero enabled, or minus 2 if not. You asked about the number of hosts. That will be 32 minus the number of network bits, minus two. So calculate it as (2^(32-20))-2, or (2^12)-2 = 4094 


Q122. - (Topic 4) 

How many addresses will be available for dynamic NAT translation when a router is configured with the following commands? 

Router(config)#ip nat pool TAME 209.165.201.23 209.165.201.30 netmask 

255.255.255.224 

Router(config)#ip nat inside source list 9 pool TAME 

A. 7 

B. 8 

C. 9 

D. 10 

E. 24 

F. 32 

Answer:

Explanation: 

209.165.201.23 to 209.165.201.30 provides for 8 addresses. 


Q123. - (Topic 7) 

Refer to the exhibit. 

Which statement describes the effect of this configuration? 

A. The VLAN 10 VTP configuration is displayed. 

B. VLAN 10 spanning-tree output is displayed. 

C. The VLAN 10 configuration is saved when the router exits VLAN configuration mode. 

D. VLAN 10 is added to the VLAN database. 

Answer:


Q124. - (Topic 5) 

Refer to the exhibit. 

A user cannot reach any web sites on the Internet, but others in the department are not 

having a problem. 

What is the most likely cause of the problem? 

A. IP routing is not enabled. 

B. The default gateway is not in the same subnet. 

C. A DNS server address is not reachable by the PC. 

D. A DHCP server address is not reachable by the PC. 

E. NAT has not been configured on the router that connects to the Internet. 

Answer:

Explanation: 

Answer C is only answer that makes sense. IP routing does not need to be enabled on PC’s, this is a router function. We can see from the output that the PC and default gateway are on the same subnet. DHCP has not been enabled on this PC so it has been configured with a static address so reaching the DHCP server is not the issue. Finally, NAT must be configured correctly or the other users in the department would also be having issues. 


Q125. - (Topic 3) 

An administrator is in the process of changing the configuration of a router. What command will allow the administrator to check the changes that have been made prior to saving the new configuration? 

A. Router# show startup-config 

B. Router# show current-config 

C. Router# show running-config 

D. Router# show memory 

E. Router# show flash 

F. Router# show processes 

Answer:

Explanation: 

This command followed by the appropriate parameter will show the running config hence the admin will be able to see what changes have been made, and then they can be saved. 


Q126. - (Topic 1) 

Which two characteristics describe the access layer of the hierarchical network design model? (Choose two.) 

A. layer 3 support 

B. port security 

C. redundant components 

D. VLANs 

E. PoE 

Answer: B,D 

Explanation: 

Access layer The main purpose of the access layer is to provide direct connection to devices on the network and controlling which devices are allowed to communicate over it. The access layer interfaces with end devices, such as PCs, printers, and IP phones, to provide access to the rest of the network. The access layer can include routers, switches, bridges, hubs, and wireless access points (AP). 

Switch features in the Access layer: 

...... 

Port security 

VLANs 

Fast Ethernet/Gigabit Ethernet 

Power over Ethernet (PoE) 

Link aggregation 

Quality of Service (QoS) 

References: http://www.ciscopath.com/content/61/ http://www.mcmcse.com/cisco/guides/hierarchical_model.shtml 

Topic 2, LAN Switching Technologies 


Q127. - (Topic 5) 

A receiving host has failed to receive all of the segments that it should acknowledge. What can the host do to improve the reliability of this communication session? 

A. decrease the window size 

B. use a different source port for the session 

C. decrease the sequence number 

D. obtain a new IP address from the DHCP server 

E. start a new session using UDP 

Answer: A Explanation: 

The Window bit in the header determines the number of segments that can be sent at a time. This is done to avoid overwhelming the destination. At the start of the session the window in small but it increases over time. The destination host can also decrease the window to slow down the flow. Hence the window is called the sliding window. When the source has sent the number of segments allowed by the window, it cannot send any further segments till an acknowledgement is received from the destination. On networks with high error rates or issues, decreasing the window size can result in more reliable transmission, as the receiver will need to acknowledge fewer segments. With a large window size, the sender will need to resend all the frames if a single one is not received by the receiver. 


Q128. - (Topic 3) 

Which two statements describe characteristics of IPv6 unicast addressing? (Choose two.) 

A. Global addresses start with 2000::/3. 

B. Link-local addresses start with FE00:/12. 

C. Link-local addresses start with FF00::/10. 

D. There is only one loopback address and it is ::1. 

E. If a global address is assigned to an interface, then that is the only allowable address for the interface. 

Answer: A,D 


Q129. - (Topic 1) 

Refer to the exhibit. 

As packets travel from Mary to Robert, which three devices will use the destination MAC address of the packet to determine a forwarding path? (Choose three.) 

A. Hub1 

B. Switch1 

C. Router1 

D. Switch2 

E. Router2 

F. Switch3 

Answer: B,D,F 

Explanation: 

Switches use the destination MAC address information for forwarding traffic, while routers use the destination IP address information. Local Area Networks employ Layer 2 Switches and Bridges to forward and filter network traffic. Switches and Bridges operate at the Data Link Layer of the Open System Interconnect Model (OSI). Since Switches and Bridges operate at the Layer 2 they operate more intelligently than hubs, which work at Layer 1 (Physical Layer) of the OSI. Because the switches and bridges are able to listen to the traffic on the wire to examine the source and destination MAC address. Being able to listen to the traffic also allows the switches and bridges to compile a MAC address table to better filter and forward network traffic. To accomplish the above functions switches and bridges carry out the following tasks: MAC address learning by a switch or a bridge is accomplished by the same method. The switch or bridge listens to each device connected to each of its ports and scan the incoming frame for the source MAC address. This creates a MAC address to port map that is cataloged in the switches/bridge MAC database. Another name for the MAC address table is content addressable memory or CAM table. When a switch or bridge is listening to the network traffic, it receives each frame and compares it to the MAC address table. By checking the MAC table the switch/ bridge are able o determine which port the frame came in on. If the frame is on the MAC table the frame is filtered or transmitted on only that port. If the switch determines that the frame is not on the MAC table, the frame is forwarded out to all ports except the incoming port. 


Q130. - (Topic 5) 

Refer to the exhibit. 

An administrator cannot connect from R1 to R2. To troubleshoot this problem, the administrator has entered the command shown in the exhibit. Based on the output shown, what could be the problem? 

A. The serial interface is configured for half duplex. 

B. The serial interface does not have a cable attached. 

C. The serial interface has the wrong type of cable attached. 

D. The serial interface is configured for the wrong frame size. 

E. The serial interface has a full buffer. 

Answer:

Explanation: 

http://www.thebryantadvantage.com/CCNACertificationExamTutorialDirectlyConnectedSeri 

alInterfaces.htm 

Since the output is not forthcoming it shows that the type of cable attached is wrong, 

though the cable is connected since it shows the cable type. 

According to the figure DTE cable should connect to R1 on interface but while examining 

using show controllers serial 0/0 command it showing that a DCE is connected so the 

wrong type of cable is being used.